I'm going to go out on a limb here and assume he meant number 7 from the statistics section of the test. As for how they got the numbers on the key, I was able to get them by doing the Chi-Square test in the TI-84. From what I've tested, it seems like how you organize your numbers does not really matter so long as you are consistent. If you've ever worked with similar triangles, I believe its a similar concept. You would either want to set it up as:Nerd_Bunny wrote:I'm currently working on finding a good way to calculate this. Apparently a method I got from a practice test was wrong, so I gave out some misinformation earlier. So far it's been hard finding ways to calculate chi-squares in an epidemiology context, but I'm trying. I'll share the correct calculations here once I find them.UTF-8 U+6211 U+662F wrote: I don't know too much about chi squared distributions, but I would assume the "expected" would be the null hypothesis, i.e. that there is no association between the exposure and the condition, and thus the expected value of people affected by the condition would be the attack rate of the whole population times the population exposed.
Sorry for double post.
EDIT: If anyone could look at the 2017 Princeton test and figure out how they got the answer to question 7 all our problems will be solved. It'a on the test exchange. I'll link to the test and key:
https://scioly.org/tests/files/diseased ... n_test.pdf
https://scioly.org/tests/files/diseased ... on_key.pdf
Category 1 Category 2
Yes 41 64
No 216 180
Or:
Yes No
C1 41 216
C2 64 180
But in this scenario C1 represents Placebo, C2 represents Drug A, and Yes and no represent Symptoms relieved or not relieved.
Whenever you set up your matrix like the tables above and perform the test in the calculator, you'll find that it stores the expected values in a second matrix that you can then go and view to get the answers they got on the key. The calculator gave me a p value of .0047 and a matrix of
53.862 203.14
51.138 192.86
for the expected values.